timberlake inorganic ch 10 chemistry test
moment (in Bohr magnetons) of [Mn(H2O)6]^2+. Solution: Mn^2+ has 5 unpaired electrons. Magnetic moment μ = √[n(n+2)] where n=5, so μ ≈ √(5×7)=√35≈5.92 Bohr magnetons. Descriptive and Conceptual Questions Questions may ask about the stability of certain oxidation states or the color of co